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1312511023045 = 5431609053839
BaseRepresentation
bin10011000110010111110…
…000001101011111000101
311122110211011001021102001
4103012113300031133011
5133001010310214140
62442543110145301
7163553150422255
oct23062760153705
94573734037361
101312511023045
114666a6289a62
12192459352231
1396a000a3461
1447750dcb965
152421c489e9a
hex13197c0d7c5

1312511023045 has 8 divisors (see below), whose sum is σ = 1578667553280. Its totient is φ = 1047572601360.

The previous prime is 1312511023027. The next prime is 1312511023069. The reversal of 1312511023045 is 5403201152131.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a de Polignac number, because none of the positive numbers 2k-1312511023045 is a prime.

It is a super-2 number, since 2×13125110230452 (a number of 25 digits) contains 22 as substring.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 304524765 + ... + 304529074.

It is an arithmetic number, because the mean of its divisors is an integer number (197333444160).

Almost surely, 21312511023045 is an apocalyptic number.

It is an amenable number.

1312511023045 is a deficient number, since it is larger than the sum of its proper divisors (266156530235).

1312511023045 is an equidigital number, since it uses as much as digits as its factorization.

1312511023045 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 609054275.

The product of its (nonzero) digits is 3600, while the sum is 28.

Adding to 1312511023045 its reverse (5403201152131), we get a palindrome (6715712175176).

The spelling of 1312511023045 in words is "one trillion, three hundred twelve billion, five hundred eleven million, twenty-three thousand, forty-five".

Divisors: 1 5 431 2155 609053839 3045269195 262502204609 1312511023045