Search a number
-
+
131252106553 = 433052374571
BaseRepresentation
bin111101000111100111…
…1000011010100111001
3110112210011222211220121
41322033033003110321
54122301014402203
6140144004053241
712324356332531
oct1721717032471
9415704884817
10131252106553
1150733435337
1221530094221
13c4b9411199
1464d18c04c1
153632c430bd
hex1e8f3c3539

131252106553 has 4 divisors (see below), whose sum is σ = 134304481168. Its totient is φ = 128199731940.

The previous prime is 131252106539. The next prime is 131252106563. The reversal of 131252106553 is 355601252131.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 131252106553 - 213 = 131252098361 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (131252106563) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1526187243 + ... + 1526187328.

It is an arithmetic number, because the mean of its divisors is an integer number (33576120292).

Almost surely, 2131252106553 is an apocalyptic number.

It is an amenable number.

131252106553 is a deficient number, since it is larger than the sum of its proper divisors (3052374615).

131252106553 is an equidigital number, since it uses as much as digits as its factorization.

131252106553 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3052374614.

The product of its (nonzero) digits is 27000, while the sum is 34.

Adding to 131252106553 its reverse (355601252131), we get a palindrome (486853358684).

The spelling of 131252106553 in words is "one hundred thirty-one billion, two hundred fifty-two million, one hundred six thousand, five hundred fifty-three".

Divisors: 1 43 3052374571 131252106553