13125243072146 has 4 divisors (see below), whose sum is σ = 19687864608222. Its totient is φ = 6562621536072.

The previous prime is 13125243072133. The next prime is 13125243072163. The reversal of 13125243072146 is 64127034252131.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 12889256005921 + 235987066225 = 3590161^2 + 485785^2 .

It is a super-3 number, since 3×13125243072146³ (a number of 40 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a Curzon number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (29) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3281310768035 + ... + 3281310768038.

Almost surely, 2^{13125243072146} is an apocalyptic number.

13125243072146 is a deficient number, since it is larger than the sum of its proper divisors (6562621536076).

13125243072146 is an equidigital number, since it uses as much as digits as its factorization.

13125243072146 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 6562621536075.

The product of its (nonzero) digits is 241920, while the sum is 41.

The spelling of 13125243072146 in words is "thirteen trillion, one hundred twenty-five billion, two hundred forty-three million, seventy-two thousand, one hundred forty-six".