Base | Representation |
---|---|
bin | 10011000110011000111… |
… | …000101001111110100011 |
3 | 11122110212110210010021000 |
4 | 103012120320221332203 |
5 | 133001030140422430 |
6 | 2442545025203043 |
7 | 163553501016645 |
oct | 23063070517643 |
9 | 4573773703230 |
10 | 1312530014115 |
11 | 466705a80261 |
12 | 192463790483 |
13 | 96a03cc2588 |
14 | 47753732895 |
15 | 2421de8be60 |
hex | 13198e29fa3 |
1312530014115 has 32 divisors (see below), whose sum is σ = 2333451735360. Its totient is φ = 699996494592.
The previous prime is 1312530014101. The next prime is 1312530014143. The reversal of 1312530014115 is 5114100352131.
1312530014115 is a `hidden beast` number, since 1 + 3 + 1 + 2 + 530 + 0 + 14 + 115 = 666.
It is not a de Polignac number, because 1312530014115 - 28 = 1312530013859 is a prime.
It is a Harshad number since it is a multiple of its sum of digits (27).
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 5630967 + ... + 5859423.
It is an arithmetic number, because the mean of its divisors is an integer number (72920366730).
Almost surely, 21312530014115 is an apocalyptic number.
1312530014115 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
1312530014115 is a deficient number, since it is larger than the sum of its proper divisors (1020921721245).
1312530014115 is a wasteful number, since it uses less digits than its factorization.
1312530014115 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 271028 (or 271022 counting only the distinct ones).
The product of its (nonzero) digits is 1800, while the sum is 27.
Adding to 1312530014115 its reverse (5114100352131), we get a palindrome (6426630366246).
The spelling of 1312530014115 in words is "one trillion, three hundred twelve billion, five hundred thirty million, fourteen thousand, one hundred fifteen".
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