13125402410023 has 8 divisors (see below), whose sum is σ = 13719168337248. Its totient is φ = 12533561170944.

The previous prime is 13125402410017. The next prime is 13125402410051. The reversal of 13125402410023 is 32001420452131.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-13125402410023 is a prime.

It is a super-2 number, since 2×13125402410023² (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 13125402409973 and 13125402410000.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13125402410063) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (31) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 481158090 + ... + 481185367.

It is an arithmetic number, because the mean of its divisors is an integer number (1714896042156).

Almost surely, 2^{13125402410023} is an apocalyptic number.

13125402410023 is a deficient number, since it is larger than the sum of its proper divisors (593765927225).

13125402410023 is an equidigital number, since it uses as much as digits as its factorization.

13125402410023 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 962344073.

The product of its (nonzero) digits is 5760, while the sum is 28.

Adding to 13125402410023 its reverse (32001420452131), we get a palindrome (45126822862154).

The spelling of 13125402410023 in words is "thirteen trillion, one hundred twenty-five billion, four hundred two million, four hundred ten thousand, twenty-three".