Base | Representation |
---|---|
bin | 1011111011111111111100… |
… | …0110111111011101001111 |
3 | 1201110202222001100021201120 |
4 | 2332333333012333131033 |
5 | 3210021312202042033 |
6 | 43525421115212023 |
7 | 2523164526434262 |
oct | 276777706773517 |
9 | 51422861307646 |
10 | 13125405112143 |
11 | 42004a9009645 |
12 | 157b95b747013 |
13 | 74294991279c |
14 | 3353b7164cd9 |
15 | 17b64de171b3 |
hex | befff1bf74f |
13125405112143 has 8 divisors (see below), whose sum is σ = 17501530686000. Its totient is φ = 8749774806528.
The previous prime is 13125405112139. The next prime is 13125405112151. The reversal of 13125405112143 is 34121150452131.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 13125405112143 - 22 = 13125405112139 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13125405112103) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 123755218 + ... + 123861231.
It is an arithmetic number, because the mean of its divisors is an integer number (2187691335750).
Almost surely, 213125405112143 is an apocalyptic number.
13125405112143 is a deficient number, since it is larger than the sum of its proper divisors (4376125573857).
13125405112143 is a wasteful number, since it uses less digits than its factorization.
13125405112143 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 247634121.
The product of its (nonzero) digits is 14400, while the sum is 33.
Adding to 13125405112143 its reverse (34121150452131), we get a palindrome (47246555564274).
The spelling of 13125405112143 in words is "thirteen trillion, one hundred twenty-five billion, four hundred five million, one hundred twelve thousand, one hundred forty-three".
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