13125405231031 has 4 divisors (see below), whose sum is σ = 13430647213192. Its totient is φ = 12820163248872.

The previous prime is 13125405231007. The next prime is 13125405231091. The reversal of 13125405231031 is 13013250452131.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 13125405231031 - 2¹⁵ = 13125405198263 is a prime.

It is a super-2 number, since 2×13125405231031² (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 13125405230984 and 13125405231002.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13125405231091) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 152620991016 + ... + 152620991101.

It is an arithmetic number, because the mean of its divisors is an integer number (3357661803298).

Almost surely, 2^{13125405231031} is an apocalyptic number.

13125405231031 is a deficient number, since it is larger than the sum of its proper divisors (305241982161).

13125405231031 is an equidigital number, since it uses as much as digits as its factorization.

13125405231031 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 305241982160.

The product of its (nonzero) digits is 10800, while the sum is 31.

Adding to 13125405231031 its reverse (13013250452131), we get a palindrome (26138655683162).

The spelling of 13125405231031 in words is "thirteen trillion, one hundred twenty-five billion, four hundred five million, two hundred thirty-one thousand, thirty-one".