Base | Representation |
---|---|
bin | 111101000111101011… |
… | …1011110001000011101 |
3 | 110112210100010222021102 |
4 | 1322033113132020131 |
5 | 4122302101013001 |
6 | 140144123242445 |
7 | 12324414154013 |
oct | 1721727361035 |
9 | 415710128242 |
10 | 131254313501 |
11 | 50734702463 |
12 | 21530979425 |
13 | c4b9a0487c |
14 | 64d1cd68b3 |
15 | 363302be6b |
hex | 1e8f5de21d |
131254313501 has 4 divisors (see below), whose sum is σ = 131301751872. Its totient is φ = 131206875132.
The previous prime is 131254313483. The next prime is 131254313549. The reversal of 131254313501 is 105313452131.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 105313452131 = 15233 ⋅6913507.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-131254313501 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (131254313581) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 23715035 + ... + 23720568.
It is an arithmetic number, because the mean of its divisors is an integer number (32825437968).
Almost surely, 2131254313501 is an apocalyptic number.
It is an amenable number.
131254313501 is a deficient number, since it is larger than the sum of its proper divisors (47438371).
131254313501 is an equidigital number, since it uses as much as digits as its factorization.
131254313501 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 47438370.
The product of its (nonzero) digits is 5400, while the sum is 29.
Adding to 131254313501 its reverse (105313452131), we get a palindrome (236567765632).
The spelling of 131254313501 in words is "one hundred thirty-one billion, two hundred fifty-four million, three hundred thirteen thousand, five hundred one".
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