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131254313501 = 276747435603
BaseRepresentation
bin111101000111101011…
…1011110001000011101
3110112210100010222021102
41322033113132020131
54122302101013001
6140144123242445
712324414154013
oct1721727361035
9415710128242
10131254313501
1150734702463
1221530979425
13c4b9a0487c
1464d1cd68b3
15363302be6b
hex1e8f5de21d

131254313501 has 4 divisors (see below), whose sum is σ = 131301751872. Its totient is φ = 131206875132.

The previous prime is 131254313483. The next prime is 131254313549. The reversal of 131254313501 is 105313452131.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 105313452131 = 152336913507.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-131254313501 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (131254313581) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 23715035 + ... + 23720568.

It is an arithmetic number, because the mean of its divisors is an integer number (32825437968).

Almost surely, 2131254313501 is an apocalyptic number.

It is an amenable number.

131254313501 is a deficient number, since it is larger than the sum of its proper divisors (47438371).

131254313501 is an equidigital number, since it uses as much as digits as its factorization.

131254313501 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 47438370.

The product of its (nonzero) digits is 5400, while the sum is 29.

Adding to 131254313501 its reverse (105313452131), we get a palindrome (236567765632).

The spelling of 131254313501 in words is "one hundred thirty-one billion, two hundred fifty-four million, three hundred thirteen thousand, five hundred one".

Divisors: 1 2767 47435603 131254313501