13125440431003 has 4 divisors (see below), whose sum is σ = 13430683231768. Its totient is φ = 12820197630240.

The previous prime is 13125440430983. The next prime is 13125440431043. The reversal of 13125440431003 is 30013404452131.

13125440431003 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 13125440431003 - 2⁹ = 13125440430491 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13125440431043) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 152621400318 + ... + 152621400403.

It is an arithmetic number, because the mean of its divisors is an integer number (3357670807942).

Almost surely, 2^{13125440431003} is an apocalyptic number.

13125440431003 is a deficient number, since it is larger than the sum of its proper divisors (305242800765).

13125440431003 is an equidigital number, since it uses as much as digits as its factorization.

13125440431003 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 305242800764.

The product of its (nonzero) digits is 17280, while the sum is 31.

Adding to 13125440431003 its reverse (30013404452131), we get a palindrome (43138844883134).

The spelling of 13125440431003 in words is "thirteen trillion, one hundred twenty-five billion, four hundred forty million, four hundred thirty-one thousand, three".