Base | Representation |
---|---|
bin | 1011111100000000000100… |
… | …1101101110001111000011 |
3 | 1201110210001111210200010222 |
4 | 2333000001031232033003 |
5 | 3210021400222243133 |
6 | 43525424420213255 |
7 | 2523165435564653 |
oct | 277000115561703 |
9 | 51423044720128 |
10 | 13125440431043 |
11 | 4200516a42216 |
12 | 157b96b53a22b |
13 | 74295402a745 |
14 | 3353bbb1a363 |
15 | 17b652091e98 |
hex | bf00136e3c3 |
13125440431043 has 2 divisors, whose sum is σ = 13125440431044. Its totient is φ = 13125440431042.
The previous prime is 13125440430983. The next prime is 13125440431079. The reversal of 13125440431043 is 34013404452131.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 13125440431043 - 26 = 13125440430979 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 13125440430994 and 13125440431012.
It is not a weakly prime, because it can be changed into another prime (13125440439043) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6562720215521 + 6562720215522.
It is an arithmetic number, because the mean of its divisors is an integer number (6562720215522).
Almost surely, 213125440431043 is an apocalyptic number.
13125440431043 is a deficient number, since it is larger than the sum of its proper divisors (1).
13125440431043 is an equidigital number, since it uses as much as digits as its factorization.
13125440431043 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 69120, while the sum is 35.
Adding to 13125440431043 its reverse (34013404452131), we get a palindrome (47138844883174).
The spelling of 13125440431043 in words is "thirteen trillion, one hundred twenty-five billion, four hundred forty million, four hundred thirty-one thousand, forty-three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.066 sec. • engine limits •