1312544450153 has 4 divisors (see below), whose sum is σ = 1330524511188. Its totient is φ = 1294564389120.

The previous prime is 1312544450141. The next prime is 1312544450159. The reversal of 1312544450153 is 3510544452131.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 236237797849 + 1076306652304 = 486043^2 + 1037452^2 .

It is a cyclic number.

It is not a de Polignac number, because 1312544450153 - 2¹⁴ = 1312544433769 is a prime.

It is a super-3 number, since 3×1312544450153³ (a number of 37 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1312544450159) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 8990030408 + ... + 8990030553.

It is an arithmetic number, because the mean of its divisors is an integer number (332631127797).

Almost surely, 2^{1312544450153} is an apocalyptic number.

It is an amenable number.

1312544450153 is a deficient number, since it is larger than the sum of its proper divisors (17980061035).

1312544450153 is an equidigital number, since it uses as much as digits as its factorization.

1312544450153 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 17980061034.

The product of its (nonzero) digits is 144000, while the sum is 38.

The spelling of 1312544450153 in words is "one trillion, three hundred twelve billion, five hundred forty-four million, four hundred fifty thousand, one hundred fifty-three".