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13125444502015 = 53301795240503
BaseRepresentation
bin1011111100000000000101…
…1101010000000111111111
31201110210001210110111110201
42333000001131100013333
53210021402243031030
643525425043344331
72523165515311456
oct277000135200777
951423053414421
1013125444502015
11420051927285a
12157b9709820a7
13742954b246c1
143353bc499b9d
1517b6525e82ca
hexbf0017501ff

13125444502015 has 8 divisors (see below), whose sum is σ = 15755304865248. Its totient is φ = 10497174626400.

The previous prime is 13125444502007. The next prime is 13125444502039. The reversal of 13125444502015 is 51020544452131.

13125444502015 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 13125444502015 - 23 = 13125444502007 is a prime.

It is a Duffinian number.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 397603747 + ... + 397636756.

It is an arithmetic number, because the mean of its divisors is an integer number (1969413108156).

Almost surely, 213125444502015 is an apocalyptic number.

13125444502015 is a deficient number, since it is larger than the sum of its proper divisors (2629860363233).

13125444502015 is an equidigital number, since it uses as much as digits as its factorization.

13125444502015 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 795243809.

The product of its (nonzero) digits is 96000, while the sum is 37.

Adding to 13125444502015 its reverse (51020544452131), we get a palindrome (64145988954146).

The spelling of 13125444502015 in words is "thirteen trillion, one hundred twenty-five billion, four hundred forty-four million, five hundred two thousand, fifteen".

Divisors: 1 5 3301 16505 795240503 3976202515 2625088900403 13125444502015