Base | Representation |
---|---|
bin | 1011111100000000000101… |
… | …1101010000000111111111 |
3 | 1201110210001210110111110201 |
4 | 2333000001131100013333 |
5 | 3210021402243031030 |
6 | 43525425043344331 |
7 | 2523165515311456 |
oct | 277000135200777 |
9 | 51423053414421 |
10 | 13125444502015 |
11 | 420051927285a |
12 | 157b9709820a7 |
13 | 742954b246c1 |
14 | 3353bc499b9d |
15 | 17b6525e82ca |
hex | bf0017501ff |
13125444502015 has 8 divisors (see below), whose sum is σ = 15755304865248. Its totient is φ = 10497174626400.
The previous prime is 13125444502007. The next prime is 13125444502039. The reversal of 13125444502015 is 51020544452131.
13125444502015 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 13125444502015 - 23 = 13125444502007 is a prime.
It is a Duffinian number.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 397603747 + ... + 397636756.
It is an arithmetic number, because the mean of its divisors is an integer number (1969413108156).
Almost surely, 213125444502015 is an apocalyptic number.
13125444502015 is a deficient number, since it is larger than the sum of its proper divisors (2629860363233).
13125444502015 is an equidigital number, since it uses as much as digits as its factorization.
13125444502015 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 795243809.
The product of its (nonzero) digits is 96000, while the sum is 37.
Adding to 13125444502015 its reverse (51020544452131), we get a palindrome (64145988954146).
The spelling of 13125444502015 in words is "thirteen trillion, one hundred twenty-five billion, four hundred forty-four million, five hundred two thousand, fifteen".
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