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13125445121103 = 37625021196243
BaseRepresentation
bin1011111100000000000101…
…1111100111010001001111
31201110210001211121221200220
42333000001133213101033
53210021402422333403
643525425104522423
72523165523500420
oct277000137472117
951423054557626
1013125445121103
1142005196559a7
12157b971020413
13742954cb0423
143353bc5bb647
1517b6526bb953
hexbf0017e744f

13125445121103 has 8 divisors (see below), whose sum is σ = 20000678279808. Its totient is φ = 7500254354904.

The previous prime is 13125445121093. The next prime is 13125445121119. The reversal of 13125445121103 is 30112154452131.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 13125445121103 - 221 = 13125443023951 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13125445121143) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 312510598101 + ... + 312510598142.

It is an arithmetic number, because the mean of its divisors is an integer number (2500084784976).

Almost surely, 213125445121103 is an apocalyptic number.

13125445121103 is a deficient number, since it is larger than the sum of its proper divisors (6875233158705).

13125445121103 is an equidigital number, since it uses as much as digits as its factorization.

13125445121103 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 625021196253.

The product of its (nonzero) digits is 14400, while the sum is 33.

Adding to 13125445121103 its reverse (30112154452131), we get a palindrome (43237599573234).

The spelling of 13125445121103 in words is "thirteen trillion, one hundred twenty-five billion, four hundred forty-five million, one hundred twenty-one thousand, one hundred three".

Divisors: 1 3 7 21 625021196243 1875063588729 4375148373701 13125445121103