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131255520031 = 177720912943
BaseRepresentation
bin111101000111101110…
…0000100101100011111
3110112210102102021022201
41322033130010230133
54122302403120111
6140144205152331
712324430340416
oct1721734045437
9415712367281
10131255520031
1150735356999
122153125b6a7
13c4ba037aac
1464d212c47d
1536331b96c1
hex1e8f704b1f

131255520031 has 4 divisors (see below), whose sum is σ = 138976432992. Its totient is φ = 123534607072.

The previous prime is 131255519971. The next prime is 131255520037. The reversal of 131255520031 is 130025552131.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 131255520031 - 215 = 131255487263 is a prime.

It is a super-2 number, since 2×1312555200312 (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (131255520037) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3860456455 + ... + 3860456488.

It is an arithmetic number, because the mean of its divisors is an integer number (34744108248).

Almost surely, 2131255520031 is an apocalyptic number.

131255520031 is a deficient number, since it is larger than the sum of its proper divisors (7720912961).

131255520031 is an equidigital number, since it uses as much as digits as its factorization.

131255520031 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 7720912960.

The product of its (nonzero) digits is 4500, while the sum is 28.

The spelling of 131255520031 in words is "one hundred thirty-one billion, two hundred fifty-five million, five hundred twenty thousand, thirty-one".

Divisors: 1 17 7720912943 131255520031