Base | Representation |
---|---|
bin | 111101000111101111… |
… | …1010111010000101011 |
3 | 110112210111001002102021 |
4 | 1322033133113100223 |
5 | 4122303113220012 |
6 | 140144235445311 |
7 | 12324440562055 |
oct | 1721737272053 |
9 | 415714032367 |
10 | 131256382507 |
11 | 50735895988 |
12 | 215315b6837 |
13 | c4ba27a533 |
14 | 64d22b48d5 |
15 | 36332da007 |
hex | 1e8f7d742b |
131256382507 has 4 divisors (see below), whose sum is σ = 133732918080. Its totient is φ = 128779846936.
The previous prime is 131256382493. The next prime is 131256382519. The reversal of 131256382507 is 705283652131.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 705283652131 = 1171 ⋅602291761.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-131256382507 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (131256382547) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1238267707 + ... + 1238267812.
It is an arithmetic number, because the mean of its divisors is an integer number (33433229520).
Almost surely, 2131256382507 is an apocalyptic number.
131256382507 is a deficient number, since it is larger than the sum of its proper divisors (2476535573).
131256382507 is an equidigital number, since it uses as much as digits as its factorization.
131256382507 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 2476535572.
The product of its (nonzero) digits is 302400, while the sum is 43.
The spelling of 131256382507 in words is "one hundred thirty-one billion, two hundred fifty-six million, three hundred eighty-two thousand, five hundred seven".
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