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13126612505233 = 53247671934061
BaseRepresentation
bin1011111100000100011100…
…0100110101001010010001
31201110220002012021012200011
42333001013010311022101
53210031300300131413
643530141005554521
72523236460213613
oct277010704651221
951426065235604
1013126612505233
114200a68604977
121580037b75a41
13742aacac5076
1433548d65adb3
1517b6bee1333d
hexbf047135291

13126612505233 has 4 divisors (see below), whose sum is σ = 13374284439348. Its totient is φ = 12878940571120.

The previous prime is 13126612505207. The next prime is 13126612505249. The reversal of 13126612505233 is 33250521662131.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 3870615542544 + 9255996962689 = 1967388^2 + 3042367^2 .

It is a cyclic number.

It is not a de Polignac number, because 13126612505233 - 213 = 13126612497041 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13126612505033) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 123835966978 + ... + 123835967083.

It is an arithmetic number, because the mean of its divisors is an integer number (3343571109837).

Almost surely, 213126612505233 is an apocalyptic number.

It is an amenable number.

13126612505233 is a deficient number, since it is larger than the sum of its proper divisors (247671934115).

13126612505233 is an equidigital number, since it uses as much as digits as its factorization.

13126612505233 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 247671934114.

The product of its (nonzero) digits is 194400, while the sum is 40.

The spelling of 13126612505233 in words is "thirteen trillion, one hundred twenty-six billion, six hundred twelve million, five hundred five thousand, two hundred thirty-three".

Divisors: 1 53 247671934061 13126612505233