1313000000143 has 4 divisors (see below), whose sum is σ = 1414000000168. Its totient is φ = 1212000000120.

The previous prime is 1313000000111. The next prime is 1313000000153. The reversal of 1313000000143 is 3410000003131.

It is a semiprime because it is the product of two primes.

It is not a de Polignac number, because 1313000000143 - 2⁵ = 1313000000111 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1313000000153) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 50499999993 + ... + 50500000018.

It is an arithmetic number, because the mean of its divisors is an integer number (353500000042).

Almost surely, 2^{1313000000143} is an apocalyptic number.

1313000000143 is a gapful number since it is divisible by the number (13) formed by its first and last digit.

1313000000143 is a deficient number, since it is larger than the sum of its proper divisors (101000000025).

1313000000143 is a wasteful number, since it uses less digits than its factorization.

1313000000143 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 101000000024.

The product of its (nonzero) digits is 108, while the sum is 16.

Adding to 1313000000143 its reverse (3410000003131), we get a palindrome (4723000003274).

The spelling of 1313000000143 in words is "one trillion, three hundred thirteen billion, one hundred forty-three", and thus it is an aban number.