Search a number
-
+
131300403131 = 217016050431
BaseRepresentation
bin111101001001000011…
…1010010011110111011
3110112220112212120100202
41322102013102132323
54122400400400011
6140152451152415
712325514004062
oct1722207223673
9415815776322
10131300403131
1150758722267
12215442a570b
13c4c6421141
1464d80931d9
1536370d323b
hex1e921d27bb

131300403131 has 4 divisors (see below), whose sum is σ = 131306475264. Its totient is φ = 131294331000.

The previous prime is 131300403119. The next prime is 131300403139. The reversal of 131300403131 is 131304003131.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 131300403131 - 26 = 131300403067 is a prime.

It is a super-2 number, since 2×1313004031312 (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (131300403139) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3003515 + ... + 3046916.

It is an arithmetic number, because the mean of its divisors is an integer number (32826618816).

Almost surely, 2131300403131 is an apocalyptic number.

131300403131 is a deficient number, since it is larger than the sum of its proper divisors (6072133).

131300403131 is an equidigital number, since it uses as much as digits as its factorization.

131300403131 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 6072132.

The product of its (nonzero) digits is 324, while the sum is 20.

Adding to 131300403131 its reverse (131304003131), we get a palindrome (262604406262).

The spelling of 131300403131 in words is "one hundred thirty-one billion, three hundred million, four hundred three thousand, one hundred thirty-one".

Divisors: 1 21701 6050431 131300403131