131300403132 has 24 divisors (see below), whose sum is σ = 316932008400. Its totient is φ = 42257600896.

The previous prime is 131300403119. The next prime is 131300403139. The reversal of 131300403132 is 231304003131.

It is a junction number, because it is equal to n+sod(n) for n = 131300403099 and 131300403108.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (131300403139) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 188649657 + ... + 188650352.

It is an arithmetic number, because the mean of its divisors is an integer number (13205500350).

Almost surely, 2^131300403132 is an apocalyptic number.

131300403132 is a gapful number since it is divisible by the number (12) formed by its first and last digit.

It is an amenable number.

131300403132 is an abundant number, since it is smaller than the sum of its proper divisors (185631605268).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

131300403132 is a wasteful number, since it uses less digits than its factorization.

131300403132 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 377300045 (or 377300043 counting only the distinct ones).

The product of its (nonzero) digits is 648, while the sum is 21.

Adding to 131300403132 its reverse (231304003131), we get a palindrome (362604406263).

The spelling of 131300403132 in words is "one hundred thirty-one billion, three hundred million, four hundred three thousand, one hundred thirty-two".