Base | Representation |
---|---|
bin | 11101110110101011000011… |
… | …000100111111011110110010 |
3 | 122012220012100020111200011120 |
4 | 131312223003010333132302 |
5 | 114202211231303320214 |
6 | 1143130325350123110 |
7 | 36441066612543603 |
oct | 3566530304773662 |
9 | 565805306450146 |
10 | 131300423104434 |
11 | 38922218936001 |
12 | 12886a9a050496 |
13 | 583576622037c |
14 | 245cd8da03daa |
15 | 102a65a6e7ea9 |
hex | 776ac313f7b2 |
131300423104434 has 16 divisors (see below), whose sum is σ = 262610080378560. Its totient is φ = 43765268673200.
The previous prime is 131300423104393. The next prime is 131300423104439. The reversal of 131300423104434 is 434401324003131.
It is a super-2 number, since 2×1313004231044342 (a number of 29 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 131300423104395 and 131300423104404.
It is not an unprimeable number, because it can be changed into a prime (131300423104439) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 384572217 + ... + 384913484.
It is an arithmetic number, because the mean of its divisors is an integer number (16413130023660).
Almost surely, 2131300423104434 is an apocalyptic number.
131300423104434 is an abundant number, since it is smaller than the sum of its proper divisors (131309657274126).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
131300423104434 is a wasteful number, since it uses less digits than its factorization.
131300423104434 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 769514145.
The product of its (nonzero) digits is 41472, while the sum is 33.
Adding to 131300423104434 its reverse (434401324003131), we get a palindrome (565701747107565).
The spelling of 131300423104434 in words is "one hundred thirty-one trillion, three hundred billion, four hundred twenty-three million, one hundred four thousand, four hundred thirty-four".
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