Base | Representation |
---|---|
bin | 111101001001000011… |
… | …1111011000110010111 |
3 | 110112220120012000120101 |
4 | 1322102013323012113 |
5 | 4122400421210440 |
6 | 140152454514531 |
7 | 12325515266104 |
oct | 1722207730627 |
9 | 415816160511 |
10 | 131300569495 |
11 | 50758826257 |
12 | 21544365a47 |
13 | c4c647ba94 |
14 | 64d80d7aab |
15 | 363711769a |
hex | 1e921fb197 |
131300569495 has 4 divisors (see below), whose sum is σ = 157560683400. Its totient is φ = 105040455592.
The previous prime is 131300569489. The next prime is 131300569501. The reversal of 131300569495 is 594965003131.
It is a semiprime because it is the product of two primes.
It is an interprime number because it is at equal distance from previous prime (131300569489) and next prime (131300569501).
It is a cyclic number.
It is not a de Polignac number, because 131300569495 - 221 = 131298472343 is a prime.
It is a super-2 number, since 2×1313005694952 (a number of 23 digits) contains 22 as substring.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 13130056945 + ... + 13130056954.
It is an arithmetic number, because the mean of its divisors is an integer number (39390170850).
Almost surely, 2131300569495 is an apocalyptic number.
131300569495 is a deficient number, since it is larger than the sum of its proper divisors (26260113905).
131300569495 is an equidigital number, since it uses as much as digits as its factorization.
131300569495 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 26260113904.
The product of its (nonzero) digits is 437400, while the sum is 46.
The spelling of 131300569495 in words is "one hundred thirty-one billion, three hundred million, five hundred sixty-nine thousand, four hundred ninety-five".
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