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1313010222301 = 3793464406919
BaseRepresentation
bin10011000110110101100…
…000100000010011011101
311122112002221101020001101
4103012311200200103131
5133003021104103201
62443104421513101
7163601421512551
oct23066540402335
94575087336041
101313010222301
11466932049828
12192578572791
1396a7c637c2b
144779b415861
152424b1e5d01
hex131b58204dd

1313010222301 has 4 divisors (see below), whose sum is σ = 1316474629600. Its totient is φ = 1309545815004.

The previous prime is 1313010222239. The next prime is 1313010222313. The reversal of 1313010222301 is 1032220103131.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1313010222301 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1313010229301) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1732203081 + ... + 1732203838.

It is an arithmetic number, because the mean of its divisors is an integer number (329118657400).

Almost surely, 21313010222301 is an apocalyptic number.

It is an amenable number.

1313010222301 is a deficient number, since it is larger than the sum of its proper divisors (3464407299).

1313010222301 is an equidigital number, since it uses as much as digits as its factorization.

1313010222301 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 3464407298.

The product of its (nonzero) digits is 216, while the sum is 19.

Adding to 1313010222301 its reverse (1032220103131), we get a palindrome (2345230325432).

The spelling of 1313010222301 in words is "one trillion, three hundred thirteen billion, ten million, two hundred twenty-two thousand, three hundred one".

Divisors: 1 379 3464406919 1313010222301