Base | Representation |
---|---|
bin | 10011000110110101100… |
… | …100111111111011110001 |
3 | 11122112010000121002010220 |
4 | 103012311210333323301 |
5 | 133003021404303213 |
6 | 2443104503043253 |
7 | 163601434520415 |
oct | 23066544777361 |
9 | 4575100532126 |
10 | 1313011400433 |
11 | 466932783997 |
12 | 192578a40529 |
13 | 96a7c95b255 |
14 | 4779b640d45 |
15 | 2424b379e23 |
hex | 131b593fef1 |
1313011400433 has 8 divisors (see below), whose sum is σ = 1751294647968. Its totient is φ = 875034543264.
The previous prime is 1313011400419. The next prime is 1313011400473. The reversal of 1313011400433 is 3340041103131.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 1313011400433 - 24 = 1313011400417 is a prime.
It is a Curzon number.
It is not an unprimeable number, because it can be changed into a prime (1313011400413) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 76587591 + ... + 76604732.
It is an arithmetic number, because the mean of its divisors is an integer number (218911830996).
Almost surely, 21313011400433 is an apocalyptic number.
It is an amenable number.
1313011400433 is a deficient number, since it is larger than the sum of its proper divisors (438283247535).
1313011400433 is a wasteful number, since it uses less digits than its factorization.
1313011400433 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 153195183.
The product of its (nonzero) digits is 1296, while the sum is 24.
Adding to 1313011400433 its reverse (3340041103131), we get a palindrome (4653052503564).
The spelling of 1313011400433 in words is "one trillion, three hundred thirteen billion, eleven million, four hundred thousand, four hundred thirty-three".
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