1313013123101 has 4 divisors (see below), whose sum is σ = 1313851039872. Its totient is φ = 1312175206332.

The previous prime is 1313013123091. The next prime is 1313013123119. The reversal of 1313013123101 is 1013213103131.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1313013123101 - 2¹⁰ = 1313013122077 is a prime.

It is a super-2 number, since 2×1313013123101² (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a Curzon number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1313013123151) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 418956035 + ... + 418959168.

It is an arithmetic number, because the mean of its divisors is an integer number (328462759968).

Almost surely, 2^{1313013123101} is an apocalyptic number.

It is an amenable number.

1313013123101 is a deficient number, since it is larger than the sum of its proper divisors (837916771).

1313013123101 is an equidigital number, since it uses as much as digits as its factorization.

1313013123101 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 837916770.

The product of its (nonzero) digits is 162, while the sum is 20.

Adding to 1313013123101 its reverse (1013213103131), we get a palindrome (2326226226232).

The spelling of 1313013123101 in words is "one trillion, three hundred thirteen billion, thirteen million, one hundred twenty-three thousand, one hundred one".