Base | Representation |
---|---|
bin | 1011111100010001100110… |
… | …0000100110101101100100 |
3 | 1201111020012020112000000002 |
4 | 2333010121200212231210 |
5 | 3210111013102021234 |
6 | 43531523204440432 |
7 | 2523423120016520 |
oct | 277043140465544 |
9 | 51436166460002 |
10 | 13130143001444 |
11 | 420250a470a37 |
12 | 15808623a9118 |
13 | 74322337b491 |
14 | 3357064b6d80 |
15 | 17b829d4627e |
hex | bf119826b64 |
13130143001444 has 12 divisors (see below), whose sum is σ = 26260286002944. Its totient is φ = 5627204143464.
The previous prime is 13130143001237. The next prime is 13130143001461. The reversal of 13130143001444 is 44410034103131.
13130143001444 is an admirable number.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 234466839284 + ... + 234466839339.
It is an arithmetic number, because the mean of its divisors is an integer number (2188357166912).
Almost surely, 213130143001444 is an apocalyptic number.
13130143001444 is a gapful number since it is divisible by the number (14) formed by its first and last digit.
It is an amenable number.
13130143001444 is a primitive abundant number, since it is smaller than the sum of its proper divisors, none of which is abundant.
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13130143001444 is a wasteful number, since it uses less digits than its factorization.
13130143001444 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 468933678634 (or 468933678632 counting only the distinct ones).
The product of its (nonzero) digits is 6912, while the sum is 29.
Adding to 13130143001444 its reverse (44410034103131), we get a palindrome (57540177104575).
The spelling of 13130143001444 in words is "thirteen trillion, one hundred thirty billion, one hundred forty-three million, one thousand, four hundred forty-four".
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