Search a number
-
+
131302000103 = 1011300019803
BaseRepresentation
bin111101001001000110…
…1011000010111100111
3110112220122212200222212
41322102031120113213
54122401303000403
6140152545314035
712325533405011
oct1722215302747
9415818780885
10131302000103
115075961307a
122154493591b
13c4c685ccb1
1464d838b1b1
1536372eb4d8
hex1e923585e7

131302000103 has 4 divisors (see below), whose sum is σ = 132602020008. Its totient is φ = 130001980200.

The previous prime is 131302000091. The next prime is 131302000117. The reversal of 131302000103 is 301000203131.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 131302000103 - 216 = 131301934567 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (131302000703) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 650009801 + ... + 650010002.

It is an arithmetic number, because the mean of its divisors is an integer number (33150505002).

Almost surely, 2131302000103 is an apocalyptic number.

131302000103 is a deficient number, since it is larger than the sum of its proper divisors (1300019905).

131302000103 is a wasteful number, since it uses less digits than its factorization.

131302000103 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1300019904.

The product of its (nonzero) digits is 54, while the sum is 14.

Adding to 131302000103 its reverse (301000203131), we get a palindrome (432302203234).

The spelling of 131302000103 in words is "one hundred thirty-one billion, three hundred two million, one hundred three", and thus it is an aban number.

Divisors: 1 101 1300019803 131302000103