Base | Representation |
---|---|
bin | 1011111100010001110110… |
… | …0000010110010101101010 |
3 | 1201111020100220200002001122 |
4 | 2333010131200112111222 |
5 | 3210111132232340432 |
6 | 43531534001415242 |
7 | 2523424562612615 |
oct | 277043540262552 |
9 | 51436326602048 |
10 | 13130210043242 |
11 | 42025442a1486 |
12 | 158088093a522 |
13 | 743234222696 |
14 | 33571136917c |
15 | 17b830b8a612 |
hex | bf11d81656a |
13130210043242 has 4 divisors (see below), whose sum is σ = 19695315064866. Its totient is φ = 6565105021620.
The previous prime is 13130210043239. The next prime is 13130210043257. The reversal of 13130210043242 is 24234001203131.
13130210043242 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 9912416263201 + 3217793780041 = 3148399^2 + 1793821^2 .
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3282552510809 + ... + 3282552510812.
Almost surely, 213130210043242 is an apocalyptic number.
13130210043242 is a deficient number, since it is larger than the sum of its proper divisors (6565105021624).
13130210043242 is an equidigital number, since it uses as much as digits as its factorization.
13130210043242 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 6565105021623.
The product of its (nonzero) digits is 3456, while the sum is 26.
Adding to 13130210043242 its reverse (24234001203131), we get a palindrome (37364211246373).
The spelling of 13130210043242 in words is "thirteen trillion, one hundred thirty billion, two hundred ten million, forty-three thousand, two hundred forty-two".
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