Base | Representation |
---|---|
bin | 1011111100010001110110… |
… | …0001010111110101111111 |
3 | 1201111020100221011201010000 |
4 | 2333010131201113311333 |
5 | 3210111132314432201 |
6 | 43531534011245343 |
7 | 2523424565111064 |
oct | 277043541276577 |
9 | 51436327151100 |
10 | 13130210311551 |
11 | 4202544465023 |
12 | 1580880a49853 |
13 | 7432342b7848 |
14 | 3357113d8c6b |
15 | 17b830bded86 |
hex | bf11d857d7f |
13130210311551 has 40 divisors (see below), whose sum is σ = 19710620536464. Its totient is φ = 8710568616960.
The previous prime is 13130210311511. The next prime is 13130210311553. The reversal of 13130210311551 is 15511301203131.
13130210311551 is a `hidden beast` number, since 1 + 3 + 1 + 3 + 0 + 2 + 103 + 1 + 1 + 551 = 666.
It is not a de Polignac number, because 13130210311551 - 27 = 13130210311423 is a prime.
It is a Harshad number since it is a multiple of its sum of digits (27).
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13130210311553) by changing a digit.
It is a polite number, since it can be written in 39 ways as a sum of consecutive naturals, for example, 14213791 + ... + 15109343.
Almost surely, 213130210311551 is an apocalyptic number.
13130210311551 is a deficient number, since it is larger than the sum of its proper divisors (6580410224913).
13130210311551 is an equidigital number, since it uses as much as digits as its factorization.
13130210311551 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 896453 (or 896444 counting only the distinct ones).
The product of its (nonzero) digits is 1350, while the sum is 27.
Adding to 13130210311551 its reverse (15511301203131), we get a palindrome (28641511514682).
The spelling of 13130210311551 in words is "thirteen trillion, one hundred thirty billion, two hundred ten million, three hundred eleven thousand, five hundred fifty-one".
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