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1313022003103 = 4330535395421
BaseRepresentation
bin10011000110110110001…
…101011100011110011111
311122112010202112202021101
4103012312031130132133
5133003032113044403
62443105522213531
7163601623610116
oct23066615343637
94575122482241
101313022003103
11466938765928
121925804b42a7
1396a81c01215
144779cc00c7d
152424c27171d
hex131b635c79f

1313022003103 has 4 divisors (see below), whose sum is σ = 1343557398568. Its totient is φ = 1282486607640.

The previous prime is 1313022003001. The next prime is 1313022003169. The reversal of 1313022003103 is 3013002203131.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1313022003103 is a prime.

It is a super-2 number, since 2×13130220031032 (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1313022003173) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 15267697668 + ... + 15267697753.

It is an arithmetic number, because the mean of its divisors is an integer number (335889349642).

Almost surely, 21313022003103 is an apocalyptic number.

1313022003103 is a deficient number, since it is larger than the sum of its proper divisors (30535395465).

1313022003103 is an equidigital number, since it uses as much as digits as its factorization.

1313022003103 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 30535395464.

The product of its (nonzero) digits is 324, while the sum is 19.

Adding to 1313022003103 its reverse (3013002203131), we get a palindrome (4326024206234).

The spelling of 1313022003103 in words is "one trillion, three hundred thirteen billion, twenty-two million, three thousand, one hundred three".

Divisors: 1 43 30535395421 1313022003103