13130224044001 has 4 divisors (see below), whose sum is σ = 13252936418352. Its totient is φ = 13007511669652.

The previous prime is 13130224043999. The next prime is 13130224044031. The reversal of 13130224044001 is 10044042203131.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 13130224044001 - 2¹ = 13130224043999 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13130224044031) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 61356187015 + ... + 61356187228.

It is an arithmetic number, because the mean of its divisors is an integer number (3313234104588).

Almost surely, 2^{13130224044001} is an apocalyptic number.

It is an amenable number.

13130224044001 is a deficient number, since it is larger than the sum of its proper divisors (122712374351).

13130224044001 is a wasteful number, since it uses less digits than its factorization.

13130224044001 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 122712374350.

The product of its (nonzero) digits is 2304, while the sum is 25.

Adding to 13130224044001 its reverse (10044042203131), we get a palindrome (23174266247132).

The spelling of 13130224044001 in words is "thirteen trillion, one hundred thirty billion, two hundred twenty-four million, forty-four thousand, one".