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13130232011043 = 372423258047521
BaseRepresentation
bin1011111100010001111011…
…0100001001100100100011
31201111020102110000011012220
42333010132310021210203
53210111203343323133
643531540104322123
72523425250415650
oct277043664114443
951436373004186
1013130232011043
114202555736194
121580888173343
13743238944694
14335714246c27
1517b832a795b3
hexbf11ed09923

13130232011043 has 16 divisors (see below), whose sum is σ = 20016230186496. Its totient is φ = 7499893121280.

The previous prime is 13130232011027. The next prime is 13130232011047. The reversal of 13130232011043 is 34011023203131.

13130232011043 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is not a de Polignac number, because 13130232011043 - 24 = 13130232011027 is a prime.

It is not an unprimeable number, because it can be changed into a prime (13130232011047) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 128972878 + ... + 129074643.

It is an arithmetic number, because the mean of its divisors is an integer number (1251014386656).

Almost surely, 213130232011043 is an apocalyptic number.

13130232011043 is a deficient number, since it is larger than the sum of its proper divisors (6885998175453).

13130232011043 is a wasteful number, since it uses less digits than its factorization.

13130232011043 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 258049954.

The product of its (nonzero) digits is 1296, while the sum is 24.

Adding to 13130232011043 its reverse (34011023203131), we get a palindrome (47141255214174).

The spelling of 13130232011043 in words is "thirteen trillion, one hundred thirty billion, two hundred thirty-two million, eleven thousand, forty-three".

Divisors: 1 3 7 21 2423 7269 16961 50883 258047521 774142563 1806332647 5418997941 625249143383 1875747430149 4376744003681 13130232011043