Base | Representation |
---|---|
bin | 1011111100010001111011… |
… | …0100001001100100100011 |
3 | 1201111020102110000011012220 |
4 | 2333010132310021210203 |
5 | 3210111203343323133 |
6 | 43531540104322123 |
7 | 2523425250415650 |
oct | 277043664114443 |
9 | 51436373004186 |
10 | 13130232011043 |
11 | 4202555736194 |
12 | 1580888173343 |
13 | 743238944694 |
14 | 335714246c27 |
15 | 17b832a795b3 |
hex | bf11ed09923 |
13130232011043 has 16 divisors (see below), whose sum is σ = 20016230186496. Its totient is φ = 7499893121280.
The previous prime is 13130232011027. The next prime is 13130232011047. The reversal of 13130232011043 is 34011023203131.
13130232011043 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is not a de Polignac number, because 13130232011043 - 24 = 13130232011027 is a prime.
It is not an unprimeable number, because it can be changed into a prime (13130232011047) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 128972878 + ... + 129074643.
It is an arithmetic number, because the mean of its divisors is an integer number (1251014386656).
Almost surely, 213130232011043 is an apocalyptic number.
13130232011043 is a deficient number, since it is larger than the sum of its proper divisors (6885998175453).
13130232011043 is a wasteful number, since it uses less digits than its factorization.
13130232011043 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 258049954.
The product of its (nonzero) digits is 1296, while the sum is 24.
Adding to 13130232011043 its reverse (34011023203131), we get a palindrome (47141255214174).
The spelling of 13130232011043 in words is "thirteen trillion, one hundred thirty billion, two hundred thirty-two million, eleven thousand, forty-three".
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