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13130234112034 = 213505009004309
BaseRepresentation
bin1011111100010001111011…
…1100001010100000100010
31201111020102120221220020101
42333010132330022200202
53210111204413041114
643531540221333014
72523425304316204
oct277043674124042
951436376856211
1013130234112034
114202556940746
121580888a0716a
137432391cba80
14335714632774
1517b832d41d74
hexbf11ef0a822

13130234112034 has 8 divisors (see below), whose sum is σ = 21210378181020. Its totient is φ = 6060108051696.

The previous prime is 13130234112019. The next prime is 13130234112053. The reversal of 13130234112034 is 43021143203131.

It can be written as a sum of positive squares in 2 ways, for example, as 11951713265625 + 1178520846409 = 3457125^2 + 1085597^2 .

It is a sphenic number, since it is the product of 3 distinct primes.

It is a junction number, because it is equal to n+sod(n) for n = 13130234111993 and 13130234112011.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 252504502129 + ... + 252504502180.

Almost surely, 213130234112034 is an apocalyptic number.

13130234112034 is a deficient number, since it is larger than the sum of its proper divisors (8080144068986).

13130234112034 is a wasteful number, since it uses less digits than its factorization.

13130234112034 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 505009004324.

The product of its (nonzero) digits is 5184, while the sum is 28.

Adding to 13130234112034 its reverse (43021143203131), we get a palindrome (56151377315165).

The spelling of 13130234112034 in words is "thirteen trillion, one hundred thirty billion, two hundred thirty-four million, one hundred twelve thousand, thirty-four".

Divisors: 1 2 13 26 505009004309 1010018008618 6565117056017 13130234112034