Base | Representation |
---|---|
bin | 10011000110110110110… |
… | …000100010100100101010 |
3 | 11122112011101212011022112 |
4 | 103012312300202210222 |
5 | 133003041441444424 |
6 | 2443110451322322 |
7 | 163602065035241 |
oct | 23066660424452 |
9 | 4575141764275 |
10 | 1313031203114 |
11 | 466942979a44 |
12 | 1925835b03a2 |
13 | 96a83aa2907 |
14 | 477a0117958 |
15 | 2424ce8c60e |
hex | 131b6c2292a |
1313031203114 has 4 divisors (see below), whose sum is σ = 1969546804674. Its totient is φ = 656515601556.
The previous prime is 1313031203111. The next prime is 1313031203119. The reversal of 1313031203114 is 4113021303131.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 1221097931089 + 91933272025 = 1105033^2 + 303205^2 .
It is a self number, because there is not a number n which added to its sum of digits gives 1313031203114.
It is not an unprimeable number, because it can be changed into a prime (1313031203111) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 328257800777 + ... + 328257800780.
Almost surely, 21313031203114 is an apocalyptic number.
1313031203114 is a deficient number, since it is larger than the sum of its proper divisors (656515601560).
1313031203114 is an equidigital number, since it uses as much as digits as its factorization.
1313031203114 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 656515601559.
The product of its (nonzero) digits is 648, while the sum is 23.
Adding to 1313031203114 its reverse (4113021303131), we get a palindrome (5426052506245).
The spelling of 1313031203114 in words is "one trillion, three hundred thirteen billion, thirty-one million, two hundred three thousand, one hundred fourteen".
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