Base | Representation |
---|---|
bin | 10011000110110110110… |
… | …011100111111000101111 |
3 | 11122112011110101012221202 |
4 | 103012312303213320233 |
5 | 133003042143330221 |
6 | 2443110520520115 |
7 | 163602104642426 |
oct | 23066663477057 |
9 | 4575143335852 |
10 | 1313032011311 |
11 | 466943381179 |
12 | 19258392003b |
13 | 96a83cc6737 |
14 | 477a02882bd |
15 | 2424d09bd0b |
hex | 131b6ce7e2f |
1313032011311 has 4 divisors (see below), whose sum is σ = 1313279618352. Its totient is φ = 1312784404272.
The previous prime is 1313032011289. The next prime is 1313032011341. The reversal of 1313032011311 is 1131102303131.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 1313032011311 - 230 = 1311958269487 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1313032011341) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 123795566 + ... + 123806171.
It is an arithmetic number, because the mean of its divisors is an integer number (328319904588).
Almost surely, 21313032011311 is an apocalyptic number.
1313032011311 is a deficient number, since it is larger than the sum of its proper divisors (247607041).
1313032011311 is an equidigital number, since it uses as much as digits as its factorization.
1313032011311 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 247607040.
The product of its (nonzero) digits is 162, while the sum is 20.
Adding to 1313032011311 its reverse (1131102303131), we get a palindrome (2444134314442).
The spelling of 1313032011311 in words is "one trillion, three hundred thirteen billion, thirty-two million, eleven thousand, three hundred eleven".
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