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1313032064746 = 2746303879691
BaseRepresentation
bin10011000110110110110…
…011110100111011101010
311122112011110110221020211
4103012312303310323222
5133003042202032441
62443110522011334
7163602105254263
oct23066663647352
94575143427224
101313032064746
11466943408336
12192583946b4a
1396a84014b5c
14477a029d96a
152424d0aca81
hex131b6cf4eea

1313032064746 has 8 divisors (see below), whose sum is σ = 1969552975104. Its totient is φ = 656514406380.

The previous prime is 1313032064731. The next prime is 1313032064761. The reversal of 1313032064746 is 6474602303131.

It is an interprime number because it is at equal distance from previous prime (1313032064731) and next prime (1313032064761).

It is a sphenic number, since it is the product of 3 distinct primes.

It is a super-2 number, since 2×13130320647462 (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1313032064699 and 1313032064708.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1052761 + ... + 1932451.

It is an arithmetic number, because the mean of its divisors is an integer number (246194121888).

Almost surely, 21313032064746 is an apocalyptic number.

1313032064746 is a deficient number, since it is larger than the sum of its proper divisors (656520910358).

1313032064746 is an equidigital number, since it uses as much as digits as its factorization.

1313032064746 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1625996.

The product of its (nonzero) digits is 217728, while the sum is 40.

Adding to 1313032064746 its reverse (6474602303131), we get a palindrome (7787634367877).

The spelling of 1313032064746 in words is "one trillion, three hundred thirteen billion, thirty-two million, sixty-four thousand, seven hundred forty-six".

Divisors: 1 2 746303 879691 1492606 1759382 656516032373 1313032064746