Base | Representation |
---|---|
bin | 11101110110101101101111… |
… | …010001010101101000000011 |
3 | 122012220110210120111220002011 |
4 | 131312231233101111220003 |
5 | 114202233140334201034 |
6 | 1143131524145433351 |
7 | 36441231322126054 |
oct | 3566555721255003 |
9 | 565813716456064 |
10 | 131303312022019 |
11 | 389234706255a5 |
12 | 1288756563b857 |
13 | 5835b068b0967 |
14 | 245d18557272b |
15 | 102a779148864 |
hex | 776b6f455a03 |
131303312022019 has 4 divisors (see below), whose sum is σ = 131303584625040. Its totient is φ = 131303039419000.
The previous prime is 131303312022017. The next prime is 131303312022073. The reversal of 131303312022019 is 910220213303131.
It is a happy number.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 131303312022019 - 21 = 131303312022017 is a prime.
It is a super-2 number, since 2×1313033120220192 (a number of 29 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (131303312022017) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 135577732 + ... + 136542769.
It is an arithmetic number, because the mean of its divisors is an integer number (32825896156260).
Almost surely, 2131303312022019 is an apocalyptic number.
131303312022019 is a deficient number, since it is larger than the sum of its proper divisors (272603021).
131303312022019 is an equidigital number, since it uses as much as digits as its factorization.
131303312022019 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 272603020.
The product of its (nonzero) digits is 5832, while the sum is 31.
The spelling of 131303312022019 in words is "one hundred thirty-one trillion, three hundred three billion, three hundred twelve million, twenty-two thousand, nineteen".
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