Base | Representation |
---|---|
bin | 1011111100010010100100… |
… | …1010000111110110110000 |
3 | 1201111020212112112111210011 |
4 | 2333010221022013312300 |
5 | 3210112032304341334 |
6 | 43532005223544304 |
7 | 2523432455416015 |
oct | 277045112076660 |
9 | 51436775474704 |
10 | 13130405543344 |
11 | 4202634690611 |
12 | 15809162bb094 |
13 | 74326589270b |
14 | 33572d2d970c |
15 | 17b842e06564 |
hex | bf129287db0 |
13130405543344 has 40 divisors (see below), whose sum is σ = 25453129700000. Its totient is φ = 6561856659456.
The previous prime is 13130405543287. The next prime is 13130405543357. The reversal of 13130405543344 is 44334550403131.
13130405543344 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a junction number, because it is equal to n+sod(n) for n = 13130405543297 and 13130405543306.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 400924282 + ... + 400957030.
It is an arithmetic number, because the mean of its divisors is an integer number (636328242500).
Almost surely, 213130405543344 is an apocalyptic number.
It is an amenable number.
13130405543344 is a deficient number, since it is larger than the sum of its proper divisors (12322724156656).
13130405543344 is a wasteful number, since it uses less digits than its factorization.
13130405543344 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 44765 (or 44759 counting only the distinct ones).
The product of its (nonzero) digits is 518400, while the sum is 40.
Adding to 13130405543344 its reverse (44334550403131), we get a palindrome (57464955946475).
The spelling of 13130405543344 in words is "thirteen trillion, one hundred thirty billion, four hundred five million, five hundred forty-three thousand, three hundred forty-four".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.076 sec. • engine limits •