Base | Representation |
---|---|
bin | 10011000110110111011… |
… | …010111000000110000010 |
3 | 11122112012011202000011222 |
4 | 103012313122320012002 |
5 | 133003102312120224 |
6 | 2443111525235042 |
7 | 163602261260432 |
oct | 23066732700602 |
9 | 4575164660158 |
10 | 1313042301314 |
11 | 46694916a207 |
12 | 192587262a82 |
13 | 96a8618a2b3 |
14 | 477a17a62c2 |
15 | 2424de30b5e |
hex | 131b76b8182 |
1313042301314 has 4 divisors (see below), whose sum is σ = 1969563451974. Its totient is φ = 656521150656.
The previous prime is 1313042301313. The next prime is 1313042301349. The reversal of 1313042301314 is 4131032403131.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 680567251225 + 632475050089 = 824965^2 + 795283^2 .
It is a super-2 number, since 2×13130423013142 (a number of 25 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (1313042301313) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 328260575327 + ... + 328260575330.
Almost surely, 21313042301314 is an apocalyptic number.
1313042301314 is a deficient number, since it is larger than the sum of its proper divisors (656521150660).
1313042301314 is an equidigital number, since it uses as much as digits as its factorization.
1313042301314 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 656521150659.
The product of its (nonzero) digits is 2592, while the sum is 26.
Adding to 1313042301314 its reverse (4131032403131), we get a palindrome (5444074704445).
The spelling of 1313042301314 in words is "one trillion, three hundred thirteen billion, forty-two million, three hundred one thousand, three hundred fourteen".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.067 sec. • engine limits •