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131304231433 = 540724284119
BaseRepresentation
bin111101001001001010…
…1111001001000001001
3110112220211002001210201
41322102111321020021
54122402340401213
6140153105212201
712325561360234
oct1722225711011
9415824061721
10131304231433
115075a8a7551
1221545631061
13c4c71617cb
1464d87ac41b
1536375dc6dd
hex1e92579209

131304231433 has 4 divisors (see below), whose sum is σ = 131328520960. Its totient is φ = 131279941908.

The previous prime is 131304231413. The next prime is 131304231463. The reversal of 131304231433 is 334132403131.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-131304231433 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (131304231413) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 12136653 + ... + 12147466.

It is an arithmetic number, because the mean of its divisors is an integer number (32832130240).

Almost surely, 2131304231433 is an apocalyptic number.

It is an amenable number.

131304231433 is a deficient number, since it is larger than the sum of its proper divisors (24289527).

131304231433 is an equidigital number, since it uses as much as digits as its factorization.

131304231433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 24289526.

The product of its (nonzero) digits is 7776, while the sum is 28.

Adding to 131304231433 its reverse (334132403131), we get a palindrome (465436634564).

The spelling of 131304231433 in words is "one hundred thirty-one billion, three hundred four million, two hundred thirty-one thousand, four hundred thirty-three".

Divisors: 1 5407 24284119 131304231433