13130432000122 has 4 divisors (see below), whose sum is σ = 19695648000186. Its totient is φ = 6565216000060.

The previous prime is 13130432000057. The next prime is 13130432000131. The reversal of 13130432000122 is 22100023403131.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 7907237144361 + 5223194855761 = 2811981^2 + 2285431^2 .

It is a junction number, because it is equal to n+sod(n) for n = 13130432000093 and 13130432000102.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3282608000029 + ... + 3282608000032.

Almost surely, 2^{13130432000122} is an apocalyptic number.

13130432000122 is a deficient number, since it is larger than the sum of its proper divisors (6565216000064).

13130432000122 is an equidigital number, since it uses as much as digits as its factorization.

13130432000122 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 6565216000063.

The product of its (nonzero) digits is 864, while the sum is 22.

Adding to 13130432000122 its reverse (22100023403131), we get a palindrome (35230455403253).

The spelling of 13130432000122 in words is "thirteen trillion, one hundred thirty billion, four hundred thirty-two million, one hundred twenty-two", and thus it is an aban number.