13130434010113 has 8 divisors (see below), whose sum is σ = 15490281597440. Its totient is φ = 10891604247840.

The previous prime is 13130434010107. The next prime is 13130434010143. The reversal of 13130434010113 is 31101043403131.

13130434010113 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-13130434010113 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13130434010143) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 30254456028 + ... + 30254456461.

It is an arithmetic number, because the mean of its divisors is an integer number (1936285199680).

Almost surely, 2^{13130434010113} is an apocalyptic number.

It is an amenable number.

13130434010113 is a deficient number, since it is larger than the sum of its proper divisors (2359847587327).

13130434010113 is an equidigital number, since it uses as much as digits as its factorization.

13130434010113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 60508912527.

The product of its (nonzero) digits is 1296, while the sum is 25.

Adding to 13130434010113 its reverse (31101043403131), we get a palindrome (44231477413244).

The spelling of 13130434010113 in words is "thirteen trillion, one hundred thirty billion, four hundred thirty-four million, ten thousand, one hundred thirteen".