13130440211041 has 4 divisors (see below), whose sum is σ = 13165085172400. Its totient is φ = 13095795249684.

The previous prime is 13130440211027. The next prime is 13130440211071. The reversal of 13130440211041 is 14011204403131.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 13130440211041 - 2⁷ = 13130440210913 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 13130440210997 and 13130440211015.

It is not an unprimeable number, because it can be changed into a prime (13130440211071) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 17322480111 + ... + 17322480868.

It is an arithmetic number, because the mean of its divisors is an integer number (3291271293100).

Almost surely, 2^{13130440211041} is an apocalyptic number.

It is an amenable number.

13130440211041 is a deficient number, since it is larger than the sum of its proper divisors (34644961359).

13130440211041 is an equidigital number, since it uses as much as digits as its factorization.

13130440211041 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 34644961358.

The product of its (nonzero) digits is 1152, while the sum is 25.

Adding to 13130440211041 its reverse (14011204403131), we get a palindrome (27141644614172).

The spelling of 13130440211041 in words is "thirteen trillion, one hundred thirty billion, four hundred forty million, two hundred eleven thousand, forty-one".