1313050445521 has 4 divisors (see below), whose sum is σ = 1313191355200. Its totient is φ = 1312909535844.

The previous prime is 1313050445491. The next prime is 1313050445527. The reversal of 1313050445521 is 1255440503131.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1313050445521 - 2²¹ = 1313048348369 is a prime.

It is a super-2 number, since 2×1313050445521² (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1313050445527) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 70440861 + ... + 70459498.

It is an arithmetic number, because the mean of its divisors is an integer number (328297838800).

Almost surely, 2^{1313050445521} is an apocalyptic number.

It is an amenable number.

1313050445521 is a deficient number, since it is larger than the sum of its proper divisors (140909679).

1313050445521 is an equidigital number, since it uses as much as digits as its factorization.

1313050445521 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 140909678.

The product of its (nonzero) digits is 36000, while the sum is 34.

Adding to 1313050445521 its reverse (1255440503131), we get a palindrome (2568490948652).

It can be divided in two parts, 1313050 and 445521, that added together give a palindrome (1758571).

The spelling of 1313050445521 in words is "one trillion, three hundred thirteen billion, fifty million, four hundred forty-five thousand, five hundred twenty-one".