1313101113231 has 4 divisors (see below), whose sum is σ = 1750801484312. Its totient is φ = 875400742152.

The previous prime is 1313101113229. The next prime is 1313101113281. The reversal of 1313101113231 is 1323111013131.

It is a semiprime because it is the product of two primes.

It is not a de Polignac number, because 1313101113231 - 2¹ = 1313101113229 is a prime.

It is a super-2 number, since 2×1313101113231² (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1313101113198 and 1313101113207.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1313101113281) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 218850185536 + ... + 218850185541.

It is an arithmetic number, because the mean of its divisors is an integer number (437700371078).

Almost surely, 2^{1313101113231} is an apocalyptic number.

1313101113231 is a deficient number, since it is larger than the sum of its proper divisors (437700371081).

1313101113231 is an equidigital number, since it uses as much as digits as its factorization.

1313101113231 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 437700371080.

The product of its (nonzero) digits is 162, while the sum is 21.

Adding to 1313101113231 its reverse (1323111013131), we get a palindrome (2636212126362).

The spelling of 1313101113231 in words is "one trillion, three hundred thirteen billion, one hundred one million, one hundred thirteen thousand, two hundred thirty-one".