Base | Representation |
---|---|
bin | 1011111100010100110101… |
… | …1000111100111001100011 |
3 | 1201111022102220100100121221 |
4 | 2333011031120330321203 |
5 | 3210114303413113103 |
6 | 43532145420355511 |
7 | 2523453516252130 |
oct | 277051530747143 |
9 | 51438386310557 |
10 | 13131013410403 |
11 | 4202916822089 |
12 | 1580a659a5b97 |
13 | 7433317b4075 |
14 | 335789d2d587 |
15 | 17b87b47a1bd |
hex | bf14d63ce63 |
13131013410403 has 16 divisors (see below), whose sum is σ = 15207564816640. Its totient is φ = 11105628620256.
The previous prime is 13131013410377. The next prime is 13131013410457. The reversal of 13131013410403 is 30401431013131.
It is a cyclic number.
It is not a de Polignac number, because 13131013410403 - 213 = 13131013402211 is a prime.
It is not an unprimeable number, because it can be changed into a prime (13131013410803) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 41238300 + ... + 41555497.
It is an arithmetic number, because the mean of its divisors is an integer number (950472801040).
Almost surely, 213131013410403 is an apocalyptic number.
13131013410403 is a deficient number, since it is larger than the sum of its proper divisors (2076551406237).
13131013410403 is a wasteful number, since it uses less digits than its factorization.
13131013410403 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 82794106.
The product of its (nonzero) digits is 1296, while the sum is 25.
Adding to 13131013410403 its reverse (30401431013131), we get a palindrome (43532444423534).
The spelling of 13131013410403 in words is "thirteen trillion, one hundred thirty-one billion, thirteen million, four hundred ten thousand, four hundred three".
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