Base | Representation |
---|---|
bin | 1011111100010100110101… |
… | …1001010100000001111001 |
3 | 1201111022102220112011120220 |
4 | 2333011031121110001321 |
5 | 3210114303424131040 |
6 | 43532145422410253 |
7 | 2523453520125264 |
oct | 277051531240171 |
9 | 51438386464526 |
10 | 13131013505145 |
11 | 4202916887288 |
12 | 1580a65a30989 |
13 | 743331818223 |
14 | 335789d55cdb |
15 | 17b87b4982d0 |
hex | bf14d654079 |
13131013505145 has 32 divisors (see below), whose sum is σ = 22195230257280. Its totient is φ = 6610665623040.
The previous prime is 13131013505117. The next prime is 13131013505167. The reversal of 13131013505145 is 54150531013131.
13131013505145 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is not a de Polignac number, because 13131013505145 - 221 = 13131011407993 is a prime.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 83086636 + ... + 83244525.
It is an arithmetic number, because the mean of its divisors is an integer number (693600945540).
Almost surely, 213131013505145 is an apocalyptic number.
13131013505145 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
It is an amenable number.
13131013505145 is a deficient number, since it is larger than the sum of its proper divisors (9064216752135).
13131013505145 is a wasteful number, since it uses less digits than its factorization.
13131013505145 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 166331465.
The product of its (nonzero) digits is 13500, while the sum is 33.
Adding to 13131013505145 its reverse (54150531013131), we get a palindrome (67281544518276).
The spelling of 13131013505145 in words is "thirteen trillion, one hundred thirty-one billion, thirteen million, five hundred five thousand, one hundred forty-five".
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