131310213133333 has 4 divisors (see below), whose sum is σ = 141410998758988. Its totient is φ = 121209427507680.

The previous prime is 131310213133291. The next prime is 131310213133339. The reversal of 131310213133333 is 333331312013131.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 14373629640049 + 116936583493284 = 3791257^2 + 10813722^2 .

It is a cyclic number.

It is not a de Polignac number, because 131310213133333 - 2²⁵ = 131310179578901 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 131310213133295 and 131310213133304.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (131310213133339) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5050392812808 + ... + 5050392812833.

It is an arithmetic number, because the mean of its divisors is an integer number (35352749689747).

Almost surely, 2^{131310213133333} is an apocalyptic number.

131310213133333 is a gapful number since it is divisible by the number (13) formed by its first and last digit.

It is an amenable number.

131310213133333 is a deficient number, since it is larger than the sum of its proper divisors (10100785625655).

131310213133333 is a wasteful number, since it uses less digits than its factorization.

131310213133333 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 10100785625654.

The product of its (nonzero) digits is 13122, while the sum is 31.

Adding to 131310213133333 its reverse (333331312013131), we get a palindrome (464641525146464).

The spelling of 131310213133333 in words is "one hundred thirty-one trillion, three hundred ten billion, two hundred thirteen million, one hundred thirty-three thousand, three hundred thirty-three".