13131022321113 has 4 divisors (see below), whose sum is σ = 17508029761488. Its totient is φ = 8754014880740.

The previous prime is 13131022321111. The next prime is 13131022321163. The reversal of 13131022321113 is 31112322013131.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 13131022321113 - 2¹ = 13131022321111 is a prime.

It is not an unprimeable number, because it can be changed into a prime (13131022321111) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2188503720183 + ... + 2188503720188.

It is an arithmetic number, because the mean of its divisors is an integer number (4377007440372).

Almost surely, 2^{13131022321113} is an apocalyptic number.

It is an amenable number.

13131022321113 is a deficient number, since it is larger than the sum of its proper divisors (4377007440375).

13131022321113 is an equidigital number, since it uses as much as digits as its factorization.

13131022321113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4377007440374.

The product of its (nonzero) digits is 648, while the sum is 24.

Adding to 13131022321113 its reverse (31112322013131), we get a palindrome (44243344334244).

The spelling of 13131022321113 in words is "thirteen trillion, one hundred thirty-one billion, twenty-two million, three hundred twenty-one thousand, one hundred thirteen".