Base | Representation |
---|---|
bin | 10011000110111011100… |
… | …001000100010100001111 |
3 | 11122112100222001221110210 |
4 | 103012323201010110033 |
5 | 133003222411024403 |
6 | 2443122422333503 |
7 | 163604054422602 |
oct | 23067341042417 |
9 | 4575328057423 |
10 | 1313111033103 |
11 | 466983a44441 |
12 | 1925a628a293 |
13 | 96a974a37ac |
14 | 477aa978339 |
15 | 24254eaab03 |
hex | 131bb84450f |
1313111033103 has 16 divisors (see below), whose sum is σ = 1779574599936. Its totient is φ = 861084362880.
The previous prime is 1313111033077. The next prime is 1313111033137. The reversal of 1313111033103 is 3013301113131.
It is not a de Polignac number, because 1313111033103 - 212 = 1313111029007 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 1313111033103.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1313111033183) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 7026525 + ... + 7210982.
It is an arithmetic number, because the mean of its divisors is an integer number (111223412496).
Almost surely, 21313111033103 is an apocalyptic number.
1313111033103 is a deficient number, since it is larger than the sum of its proper divisors (466463566833).
1313111033103 is a wasteful number, since it uses less digits than its factorization.
1313111033103 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 14238014.
The product of its (nonzero) digits is 243, while the sum is 21.
Adding to 1313111033103 its reverse (3013301113131), we get a palindrome (4326412146234).
The spelling of 1313111033103 in words is "one trillion, three hundred thirteen billion, one hundred eleven million, thirty-three thousand, one hundred three".
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