1313120113031 has 4 divisors (see below), whose sum is σ = 1313212076064. Its totient is φ = 1313028150000.

The previous prime is 1313120112977. The next prime is 1313120113051. The reversal of 1313120113031 is 1303110213131.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1313120113031 - 2¹⁴ = 1313120096647 is a prime.

It is a super-2 number, since 2×1313120113031² (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1313120112994 and 1313120113012.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1313120113051) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 45960095 + ... + 45988656.

It is an arithmetic number, because the mean of its divisors is an integer number (328303019016).

Almost surely, 2^{1313120113031} is an apocalyptic number.

1313120113031 is a deficient number, since it is larger than the sum of its proper divisors (91963033).

1313120113031 is an equidigital number, since it uses as much as digits as its factorization.

1313120113031 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 91963032.

The product of its (nonzero) digits is 162, while the sum is 20.

Adding to 1313120113031 its reverse (1303110213131), we get a palindrome (2616230326162).

The spelling of 1313120113031 in words is "one trillion, three hundred thirteen billion, one hundred twenty million, one hundred thirteen thousand, thirty-one".